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Re: [Scheme-reports] procedure identity
Taylan Ulrich B. scripsit:
> eq? is a (typically) more efficient eqv?,
I have yet to be convinced that `eq?` actually is more efficient
than `eqv?` on the safe types.
--
Real FORTRAN programmers can program FORTRAN John Cowan
in any language. --Ed Post cowan@x
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