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Re: [Scheme-reports] procedure identity

Taylan Ulrich B. scripsit:

> eq? is a (typically) more efficient eqv?, 

I have yet to be convinced that `eq?` actually is more efficient
than `eqv?` on the safe types.

Real FORTRAN programmers can program FORTRAN    John Cowan
in any language.  --Ed Post                     cowan@x

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