On 11/25/2012 04:07 PM, Mark H Weaver wrote:IMO this does the wrong thing if you have two different NaN values,
> * Significant change: Fix the NaN problem by making sure that
> two numbers can only be /substantially different/ if at
> least one of them is numerically equal to itself.
as allowed by IEEE. Neither is numerically equal to itself,
but they have different bit-patterns, and eqv? should compare
them as false.
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