Re: [Scheme-reports] Is bytevector a token?

[Takashi Kato <ktakashi@x>]

I think it's on purpose.

As my understanding (correct me if I'm wrong), <token> meant be the smallest unit that a lexer reads and <bytevector> is a compound datum that a parser needs to construct. Suppose your reader gets #u8(1 2 3) as its input, then first your lexer needs to return a token to let your parser know what type of datum needs to be constructed. Now, first the lexer returns #u8( then the parser understands this is a bytevector. However if <bytevector> is in <token> then your lexer needs to read the input as a bytevector. Then inside of the bytevector it has a delimiter and token so lexer needs to read your input recursively. I'm not good with theory but seems something is wrong.


Hope it can help you.

_/_/
Takashi Kato
E-mail: ktakashi@x




On Tuesday, 29 October 2013, 5:48, Yuichi Nishiwaki <yuichi.nishiwaki@x> wrote:
Hi, all. I'm very excited to see the final R7RS draft published. Thank
you all for the great work.
Reading the final draft, I have one question about the formal syntax
definition (7.1.1). <bytevector> is not listed in <token> line. Is it
by purpose? Or just a missing?

-- Yuichi Nishiwaki

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